退款订单列表增加金额汇总
refundOrder/list 响应增加 totalMoney(单位:分),走 $sum 聚合统计 整个筛选结果的退款金额,而不是当前这一页 —— 按渠道搜出几百笔时 只汇总当页会得出错误金额。 命中数为 0 时直接返回,不再多跑一次聚合和列表查询。 Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
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@@ -93,6 +93,29 @@ func CountRefundOrders(ctx context.Context, filter bson.M) (int64, error) {
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return count, nil
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}
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// SumRefundOrderMoney 按同一 filter 汇总退款金额(单位:分)。
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// 走聚合而不是把 money 累加在业务层,是为了统计整个查询结果而不只是当前这一页。
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func SumRefundOrderMoney(ctx context.Context, filter bson.M) (int64, error) {
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var ret []struct {
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TotalMoney int64 `bson:"totalMoney"`
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}
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pipeline := []bson.M{
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{"$match": filter},
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{"$group": bson.M{
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"_id": nil,
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"totalMoney": bson.M{"$sum": "$" + FN.RefundOrder.Money},
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}},
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}
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if err := db.Aggregate(ctx, &ret, pipeline); err != nil {
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log.Warn("refundOrderMod SumMoney failed", log.E(err), log.Any("filter", filter))
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return 0, err
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}
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if len(ret) == 0 {
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return 0, nil // 没有命中任何记录
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}
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return ret[0].TotalMoney, nil
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}
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func DelOneRefundOrder(ctx context.Context, filter bson.M) (int64, error) {
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count, err := db.DeleteOne(ctx, filter)
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if err != nil {
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